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(y+1)^2 equation

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Numerical solution:

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The solution

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       2    
(y + 1)  = 0
$$\left(y + 1\right)^{2} = 0$$
Detail solution
Expand the expression in the equation
$$\left(y + 1\right)^{2} = 0$$
We get the quadratic equation
$$y^{2} + 2 y + 1 = 0$$
This equation is of the form
a*y^2 + b*y + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$y_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$y_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 2$$
$$c = 1$$
, then
D = b^2 - 4 * a * c = 

(2)^2 - 4 * (1) * (1) = 0

Because D = 0, then the equation has one root.
y = -b/2a = -2/2/(1)

$$y_{1} = -1$$
The graph
Rapid solution [src]
y1 = -1
$$y_{1} = -1$$
y1 = -1
Sum and product of roots [src]
sum
-1
$$-1$$
=
-1
$$-1$$
product
-1
$$-1$$
=
-1
$$-1$$
-1
Numerical answer [src]
y1 = -1.0
y1 = -1.0