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(y+1)^2 equation

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Numerical solution:

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The solution

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       2    
(y + 1)  = 0
(y+1)2=0\left(y + 1\right)^{2} = 0
Simplify
Detail solution
Expand the expression in the equation
(y+1)2=0\left(y + 1\right)^{2} = 0
We get the quadratic equation
y2+2y+1=0y^{2} + 2 y + 1 = 0
This equation is of the form
a*y^2 + b*y + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
y1=D−b2ay_{1} = \frac{\sqrt{D} - b}{2 a}
y2=−D−b2ay_{2} = \frac{- \sqrt{D} - b}{2 a}
where D = b^2 - 4*a*c - it is the discriminant.
Because
a=1a = 1
b=2b = 2
c=1c = 1
, then
D = b^2 - 4 * a * c = 

(2)^2 - 4 * (1) * (1) = 0

Because D = 0, then the equation has one root.
y = -b/2a = -2/2/(1)

y1=−1y_{1} = -1
The graph
-15.0-12.5-10.0-7.5-5.0-2.50.02.55.07.510.012.50200
Plot the graph f1(x)
Plot the graph f2(x)
Rapid solution [src] 
y1 = -1
y1=−1y_{1} = -1 
y1 = -1
Sum and product of roots [src] 
sum
-1
−1-1 
=
-1
−1-1 
product
-1
−1-1 
=
-1
−1-1 
-1
Numerical answer [src] 
y1 = -1.0
y1 = -1.0
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