Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 2^x=6-x
-
Equation x^3=4
-
Equation x^2+2x+2=0
-
Equation 3/(x-5)+8/x=2
- Express {x} in terms of y where:
- -1*x-6*y=18
- 6*x-19*y=-18
- -14*x+18*y=0
- -8*x+3*y=-4
- Factor polynomial:
- x^2-x+4
- Factor squared:
- x^2-x+4
- Integral of d{x}:
- x^2-x+4
-
Identical expressions
- x^ two -x+ four = zero
- x squared minus x plus 4 equally 0
- x to the power of two minus x plus four equally zero
- x2-x+4=0
- x²-x+4=0
- x to the power of 2-x+4=0
- x^2-x+4=O
-
Similar expressions
- x^2-x-4=0
- x^2+x+4=0
x^2-x+4=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -1$$
$$c = 4$$
, then
Because D<0, then the equation
has no real roots,
but complex roots is exists.
or
$$x_{1} = \frac{1}{2} + \frac{\sqrt{15} i}{2}$$
$$x_{2} = \frac{1}{2} - \frac{\sqrt{15} i}{2}$$
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -1$$
$$c = 4$$
, then
D = b^2 - 4 * a * c =
(-1)^2 - 4 * (1) * (4) = -15
Because D<0, then the equation
has no real roots,
but complex roots is exists.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = \frac{1}{2} + \frac{\sqrt{15} i}{2}$$
$$x_{2} = \frac{1}{2} - \frac{\sqrt{15} i}{2}$$
Vieta's Theorem
it is reduced quadratic equation
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = -1$$
$$q = \frac{c}{a}$$
$$q = 4$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 1$$
$$x_{1} x_{2} = 4$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = -1$$
$$q = \frac{c}{a}$$
$$q = 4$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 1$$
$$x_{1} x_{2} = 4$$
Sum and product of roots
[src]
sum
____ ____ 1 I*\/ 15 1 I*\/ 15 - - -------- + - + -------- 2 2 2 2
$$\left(\frac{1}{2} - \frac{\sqrt{15} i}{2}\right) + \left(\frac{1}{2} + \frac{\sqrt{15} i}{2}\right)$$
=
1
$$1$$
product
/ ____\ / ____\ |1 I*\/ 15 | |1 I*\/ 15 | |- - --------|*|- + --------| \2 2 / \2 2 /
$$\left(\frac{1}{2} - \frac{\sqrt{15} i}{2}\right) \left(\frac{1}{2} + \frac{\sqrt{15} i}{2}\right)$$
=
4
$$4$$
4
Rapid solution
[src]
____
1 I*\/ 15
x1 = - - --------
2 2
$$x_{1} = \frac{1}{2} - \frac{\sqrt{15} i}{2}$$
____
1 I*\/ 15
x2 = - + --------
2 2
$$x_{2} = \frac{1}{2} + \frac{\sqrt{15} i}{2}$$
x2 = 1/2 + sqrt(15)*i/2
Numerical answer
[src]
x1 = 0.5 - 1.93649167310371*i
x2 = 0.5 + 1.93649167310371*i
x2 = 0.5 + 1.93649167310371*i
The graph