x^2-6*x+2=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -6$$
$$c = 2$$
, then
D = b^2 - 4 * a * c =
(-6)^2 - 4 * (1) * (2) = 28
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = \sqrt{7} + 3$$
$$x_{2} = 3 - \sqrt{7}$$
Vieta's Theorem
it is reduced quadratic equation
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = -6$$
$$q = \frac{c}{a}$$
$$q = 2$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 6$$
$$x_{1} x_{2} = 2$$
Sum and product of roots
[src]
___ ___
3 - \/ 7 + 3 + \/ 7
$$\left(3 - \sqrt{7}\right) + \left(\sqrt{7} + 3\right)$$
$$6$$
/ ___\ / ___\
\3 - \/ 7 /*\3 + \/ 7 /
$$\left(3 - \sqrt{7}\right) \left(\sqrt{7} + 3\right)$$
$$2$$
$$x_{1} = 3 - \sqrt{7}$$
$$x_{2} = \sqrt{7} + 3$$