Mister Exam
Other calculators
-
How to use it?
- Equation:
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Equation (x-5)/2=2*(3x/7-1/2)/3
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Equation x^4-4*x^3-2*x^2+12*x+9=0
-
Equation sin(x)=-1
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Equation cos(x)=sqrt(3)/2
- Express {x} in terms of y where:
- 18*x-20*y=-7
- 1*x-6*y=-19
- -19*x-14*y=-8
- 9*x-4*y=2
- Graphing y =:
- (x^2-1)/(x^2+1)
- Derivative of:
-
(x^2-1)/(x^2+1)
- Integral of d{x}:
-
(x^2-1)/(x^2+1)
-
Identical expressions
- (x^ two - one)/(x^ two + one)= zero
- (x squared minus 1) divide by (x squared plus 1) equally 0
- (x to the power of two minus one) divide by (x to the power of two plus one) equally zero
- (x2-1)/(x2+1)=0
- x2-1/x2+1=0
- (x²-1)/(x²+1)=0
- (x to the power of 2-1)/(x to the power of 2+1)=0
- x^2-1/x^2+1=0
- (x^2-1)/(x^2+1)=O
- (x^2-1) divide by (x^2+1)=0
-
Similar expressions
- (x^2-1)/(x^2-1)=0
- (x^2+1)/(x^2+1)=0
(x^2-1)/(x^2+1)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x^{2} - 1}{x^{2} + 1} = 0$$
the denominator
$$x^{2} + 1$$
then
Because the right side of the equation is zero, then the solution of the equation is exists if at least one of the multipliers in the left side of the equation equal to zero.
We get the equations
$$x^{2} - 1 = 0$$
solve the resulting equation:
1.
$$x^{2} - 1 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -1$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 1$$
Simplify
$$x_{2} = -1$$
Simplify
but
The final answer:
$$x_{1} = 1$$
$$x_{2} = -1$$
$$\frac{x^{2} - 1}{x^{2} + 1} = 0$$
the denominator
$$x^{2} + 1$$
then
x is not equal to -I
x is not equal to I
Because the right side of the equation is zero, then the solution of the equation is exists if at least one of the multipliers in the left side of the equation equal to zero.
We get the equations
$$x^{2} - 1 = 0$$
solve the resulting equation:
1.
$$x^{2} - 1 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -1$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (1) * (-1) = 4
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 1$$
Simplify
$$x_{2} = -1$$
Simplify
but
x is not equal to -I
x is not equal to I
The final answer:
$$x_{1} = 1$$
$$x_{2} = -1$$
Sum and product of roots
[src]
sum
0 - 1 + 1
$$\left(-1 + 0\right) + 1$$
=
0
$$0$$
product
1*-1*1
$$1 \left(-1\right) 1$$
=
-1
$$-1$$
-1
The graph