Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 8*x-3*(2*x+1)=2*x+4
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Equation 3*9^(x-1/2)-7*6^x+3*4^(x+1)=0
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Equation 9x-26=30-5x
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Equation x+19=12
- Express {x} in terms of y where:
- 12*x+14*y=-15
- -9*x-15*y=-4
- 12*x-14*y=20
- 11*x-20*y=-10
- Derivative of:
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x^3
- Integral of d{x}:
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x^3
- x^3
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Identical expressions
- x^ three = zero
- x cubed equally 0
- x to the power of three equally zero
- x3=0
- x³=0
- x to the power of 3=0
- x^3=O
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Similar expressions
- 16x^3-x=0
- 5x^3-5x=0
- sqrt(x)^3-3=0
x^3=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$x^{3} = 0$$
so
$$x = 0$$
We get the answer: x = 0
$$x^{3} = 0$$
so
$$x = 0$$
We get the answer: x = 0
Vieta's Theorem
it is reduced cubic equation
$$p x^{2} + q x + v + x^{3} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
$$v = \frac{d}{a}$$
$$v = 0$$
Vieta Formulas
$$x_{1} + x_{2} + x_{3} = - p$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = q$$
$$x_{1} x_{2} x_{3} = v$$
$$x_{1} + x_{2} + x_{3} = 0$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = 0$$
$$x_{1} x_{2} x_{3} = 0$$
$$p x^{2} + q x + v + x^{3} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
$$v = \frac{d}{a}$$
$$v = 0$$
Vieta Formulas
$$x_{1} + x_{2} + x_{3} = - p$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = q$$
$$x_{1} x_{2} x_{3} = v$$
$$x_{1} + x_{2} + x_{3} = 0$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = 0$$
$$x_{1} x_{2} x_{3} = 0$$
The graph