Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+2*x+10=0
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Equation 2^4-2*x=64
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Equation x^2+3*x+9=0
- Equation x^2-x+30=0
- Express {x} in terms of y where:
- -18*x-3*y=2
- 5*x+20*y=-4
- 20*x-8*y=13
- -16*x+18*y=9
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Identical expressions
- (x+ three)/ seven =(2x- one)/ five
- (x plus 3) divide by 7 equally (2x minus 1) divide by 5
- (x plus three) divide by seven equally (2x minus one) divide by five
- x+3/7=2x-1/5
- (x+3) divide by 7=(2x-1) divide by 5
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Similar expressions
- x+3/7=0
- ln(x^2-1)+arcsin(2*x-1)/5+1/(x-2)=0
- x+3/7=3x-2/2
- x-3/4=x+3/7
- x+3/7+10=140
- (x+3)/7=(2x+1)/5
- x+3/7=2x-1/5
- (1/2)*(y+(1/2)*x)-(1/5)*(x+2)=11
- 1/2x-1/5x=0,1
- (x-3)/7=(2x-1)/5
(x+3)/7=(2x-1)/5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{7} = \frac{2 x}{5} - \frac{22}{35}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-9\right) x}{35} = - \frac{22}{35}$$
Divide both parts of the equation by -9/35
We get the answer: x = 22/9
(x+3)/7 = (2*x-1)/5
Expand brackets in the left part
x/7+3/7 = (2*x-1)/5
Expand brackets in the right part
x/7+3/7 = 2*x/5-1/5
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{7} = \frac{2 x}{5} - \frac{22}{35}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-9\right) x}{35} = - \frac{22}{35}$$
Divide both parts of the equation by -9/35
x = -22/35 / (-9/35)
We get the answer: x = 22/9
Sum and product of roots
[src]
sum
22/9
$$\frac{22}{9}$$
=
22/9
$$\frac{22}{9}$$
product
22/9
$$\frac{22}{9}$$
=
22/9
$$\frac{22}{9}$$
22/9