Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 81*x^3+18*x^2+x=0
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Equation 6=8-5(7x-1)
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Equation 3x=28-x
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Equation 3x=2
- Express {x} in terms of y where:
- -13*x-7*y=16
- -16*x+10*y=-11
- -2*x-15*y=-1
- -14*x+5*y=-1
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Identical expressions
- x+ one / eight *(x- four / five *(x+ seven))=2x- one / six
- x plus 1 divide by 8 multiply by (x minus 4 divide by 5 multiply by (x plus 7)) equally 2x minus 1 divide by 6
- x plus one divide by eight multiply by (x minus four divide by five multiply by (x plus seven)) equally 2x minus one divide by six
- x+1/8(x-4/5(x+7))=2x-1/6
- x+1/8x-4/5x+7=2x-1/6
- x+1 divide by 8*(x-4 divide by 5*(x+7))=2x-1 divide by 6
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Similar expressions
- x+1/8*(x+4/5*(x+7))=2x-1/6
- x+1/8*(x-4/5*(x-7))=2x-1/6
- f*(x)-2*x-1/6*x^3=0
- 3/4x+5/6=(1)(1)/(2)x-1/6
- x-1/8*(x-4/5*(x+7))=2x-1/6
- (-1/3)x+1=(1/12)x-1/6
- x+1/8*(x-4/5*(x+7))=2x+1/6
x+1/8*(x-4/5*(x+7))=2x-1/6 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
4*(x + 7)
x - ---------
5
x + ------------- = 2*x - 1/6
8
$$x + \frac{x - \frac{4 \left(x + 7\right)}{5}}{8} = 2 x - \frac{1}{6}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$\frac{41 x}{40} = 2 x + \frac{8}{15}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-39\right) x}{40} = \frac{8}{15}$$
Divide both parts of the equation by -39/40
We get the answer: x = -64/117
x+1/8*(x-4/5*(x+7)) = 2*x-1/6
Expand brackets in the left part
x+1/8*x-1/8*4/5*+1/8*x+1/8*7) = 2*x-1/6
Looking for similar summands in the left part:
-7/10 + 41*x/40 = 2*x-1/6
Move free summands (without x)
from left part to right part, we given:
$$\frac{41 x}{40} = 2 x + \frac{8}{15}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-39\right) x}{40} = \frac{8}{15}$$
Divide both parts of the equation by -39/40
x = 8/15 / (-39/40)
We get the answer: x = -64/117
Sum and product of roots
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sum
-64 ---- 117
$$- \frac{64}{117}$$
=
-64 ---- 117
$$- \frac{64}{117}$$
product
-64 ---- 117
$$- \frac{64}{117}$$
=
-64 ---- 117
$$- \frac{64}{117}$$
-64/117