Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3*x^2-x-5=0
-
Equation cos(x)=-3
-
Equation -x^3+14*x^2-61*x+84=0
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Equation 16x^2=1
- Express {x} in terms of y where:
- 18*x-5*y=-2
- 13*x-2*y=5
- -1*x+4*y=5
- -19*x-15*y=11
- Derivative of:
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(x+4)^2
- Integral of d{x}:
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(x+4)^2
- Graphing y =:
- (x+4)^2
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Identical expressions
- (x+ four)^ two = zero
- (x plus 4) squared equally 0
- (x plus four) to the power of two equally zero
- (x+4)2=0
- x+42=0
- (x+4)²=0
- (x+4) to the power of 2=0
- x+4^2=0
- (x+4)^2=O
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Similar expressions
- (x-4)^2=0
(x+4)^2=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(x + 4\right)^{2} = 0$$
We get the quadratic equation
$$x^{2} + 8 x + 16 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 8$$
$$c = 16$$
, then
Because D = 0, then the equation has one root.
$$x_{1} = -4$$
$$\left(x + 4\right)^{2} = 0$$
We get the quadratic equation
$$x^{2} + 8 x + 16 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 8$$
$$c = 16$$
, then
D = b^2 - 4 * a * c =
(8)^2 - 4 * (1) * (16) = 0
Because D = 0, then the equation has one root.
x = -b/2a = -8/2/(1)
$$x_{1} = -4$$
The graph