Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation sin(2*x)=-1/2
-
Equation ||x|-4|=5
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Equation 2x^2-3x-6=x^2-4x-(2-x^2)
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Equation x+(7-2x)=10
- Express {x} in terms of y where:
- -10*x+7*y=-12
- -15*x+3*y=8
- 18*x-10*y=-9
- 19*x-7*y=-11
- Integral of d{x}:
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(x+8)/(x+2)
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Identical expressions
- (x+ eight)/(x+ two)= seven / three
- (x plus 8) divide by (x plus 2) equally 7 divide by 3
- (x plus eight) divide by (x plus two) equally seven divide by three
- x+8/x+2=7/3
- (x+8) divide by (x+2)=7 divide by 3
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Similar expressions
- (x-8)/(x+2)=7/3
- 3(4y^2+10y-7)/(16y^2-9)=(3y-7)/(3-4y)+(6y+5)(3+4y)
- 2x+(6x-5)/7=(8x+7)/3
- -(x-4)/(x+2)+(4*x+8)/(x+2)=0
- (x+8)/(x-2)=7/3
(x+8)/(x+2)=7/3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x + 8}{x + 2} = \frac{7}{3}$$
Multiply the equation sides by the denominator 2 + x
we get:
$$x + 8 = \frac{7 x}{3} + \frac{14}{3}$$
Move free summands (without x)
from left part to right part, we given:
$$x = \frac{7 x}{3} - \frac{10}{3}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{3} = - \frac{10}{3}$$
Divide both parts of the equation by -4/3
We get the answer: x = 5/2
$$\frac{x + 8}{x + 2} = \frac{7}{3}$$
Multiply the equation sides by the denominator 2 + x
we get:
$$x + 8 = \frac{7 x}{3} + \frac{14}{3}$$
Move free summands (without x)
from left part to right part, we given:
$$x = \frac{7 x}{3} - \frac{10}{3}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{3} = - \frac{10}{3}$$
Divide both parts of the equation by -4/3
x = -10/3 / (-4/3)
We get the answer: x = 5/2
Sum and product of roots
[src]
sum
5/2
$$\frac{5}{2}$$
=
5/2
$$\frac{5}{2}$$
product
5/2
$$\frac{5}{2}$$
=
5/2
$$\frac{5}{2}$$
5/2