Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation e^x=2
-
Equation 3^x=-3
-
Equation 3*x^2-7=0
-
Equation e^x-x=0
- Express {x} in terms of y where:
- 11*x+3*y=-16
- -2*x+13*y=-6
- 20*x-3*y=3
- 18*x-7*y=-4
- Integral of d{x}:
- x*(x-5)
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Identical expressions
- x*(x- five)= zero
- x multiply by (x minus 5) equally 0
- x multiply by (x minus five) equally zero
- x(x-5)=0
- xx-5=0
- x*(x-5)=O
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Similar expressions
- x*(x+5)=0
- x(x-5)=0
- x*x-5=2*x+19
- x(x-5)=1-4x
- x(x-5)*(x+5)*(x-2)=0
x*(x-5)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$x \left(x - 5\right) = 0$$
We get the quadratic equation
$$x^{2} - 5 x = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 0$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 5$$
$$x_{2} = 0$$
$$x \left(x - 5\right) = 0$$
We get the quadratic equation
$$x^{2} - 5 x = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 0$$
, then
D = b^2 - 4 * a * c =
(-5)^2 - 4 * (1) * (0) = 25
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 5$$
$$x_{2} = 0$$
The graph