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x-2^x+5 equation

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Numerical solution:

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The solution

You have entered [src]
     x        
x - 2  + 5 = 0
$$\left(- 2^{x} + x\right) + 5 = 0$$
The graph
Sum and product of roots [src]
sum
          /-log(2) \
         W|--------|
          \   32   /
3 + -5 - -----------
            log(2)  
$$\left(-5 - \frac{W\left(- \frac{\log{\left(2 \right)}}{32}\right)}{\log{\left(2 \right)}}\right) + 3$$
=
      /-log(2) \
     W|--------|
      \   32   /
-2 - -----------
        log(2)  
$$-2 - \frac{W\left(- \frac{\log{\left(2 \right)}}{32}\right)}{\log{\left(2 \right)}}$$
product
  /      /-log(2) \\
  |     W|--------||
  |      \   32   /|
3*|-5 - -----------|
  \        log(2)  /
$$3 \left(-5 - \frac{W\left(- \frac{\log{\left(2 \right)}}{32}\right)}{\log{\left(2 \right)}}\right)$$
=
         /-log(2) \
      3*W|--------|
         \   32   /
-15 - -------------
          log(2)   
$$-15 - \frac{3 W\left(- \frac{\log{\left(2 \right)}}{32}\right)}{\log{\left(2 \right)}}$$
-15 - 3*LambertW(-log(2)/32)/log(2)
Rapid solution [src]
x1 = 3
$$x_{1} = 3$$
           /-log(2) \
          W|--------|
           \   32   /
x2 = -5 - -----------
             log(2)  
$$x_{2} = -5 - \frac{W\left(- \frac{\log{\left(2 \right)}}{32}\right)}{\log{\left(2 \right)}}$$
x2 = -5 - LambertW(-log(2)/32)/log(2)
Numerical answer [src]
x1 = -4.96805022061857
x2 = 3.0
x2 = 3.0