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x-2+3(x-3)=3(4-x)-3 equation

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Numerical solution:

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The solution

You have entered [src]
x - 2 + 3*(x - 3) = 3*(4 - x) - 3
$$3 \left(x - 3\right) + \left(x - 2\right) = 3 \left(4 - x\right) - 3$$
Detail solution
Given the linear equation:
x-2+3*(x-3) = 3*(4-x)-3

Expand brackets in the left part
x-2+3*x-3*3 = 3*(4-x)-3

Expand brackets in the right part
x-2+3*x-3*3 = 3*4-3*x-3

Looking for similar summands in the left part:
-11 + 4*x = 3*4-3*x-3

Looking for similar summands in the right part:
-11 + 4*x = 9 - 3*x

Move free summands (without x)
from left part to right part, we given:
$$4 x = 20 - 3 x$$
Move the summands with the unknown x
from the right part to the left part:
$$7 x = 20$$
Divide both parts of the equation by 7
x = 20 / (7)

We get the answer: x = 20/7
The graph
Sum and product of roots [src]
sum
20/7
$$\frac{20}{7}$$
=
20/7
$$\frac{20}{7}$$
product
20/7
$$\frac{20}{7}$$
=
20/7
$$\frac{20}{7}$$
20/7
Rapid solution [src]
x1 = 20/7
$$x_{1} = \frac{20}{7}$$
x1 = 20/7
Numerical answer [src]
x1 = 2.85714285714286
x1 = 2.85714285714286