Mister Exam
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How to use it?
- Equation:
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Equation 17x-8=20x+7
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Equation 2*x^2+6*x+9=
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Equation (x-2)^2=(x-9)^2
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Equation -x=8
- Express {x} in terms of y where:
- 17*x+20*y=-12
- 17*x+16*y=7
- -5*x+6*y=19
- 18*x-14*y=-12
- Graphing y =:
- 2/3-x
- Limit of the function:
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2/3-x
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Identical expressions
- (x- two)/ five -(three x+ two)/ six = two /3-x
- (x minus 2) divide by 5 minus (3x plus 2) divide by 6 equally 2 divide by 3 minus x
- (x minus two) divide by five minus (three x plus two) divide by six equally two divide by 3 minus x
- x-2/5-3x+2/6=2/3-x
- (x-2) divide by 5-(3x+2) divide by 6=2 divide by 3-x
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Similar expressions
- (5*x+x^2)/(3-x)=0
- (x-2)/5-(3x-2)/6=2/3-x
- (x+2)^(2/3)-(x-2)^(2/3)=0
- (x-2)/5+(3x+2)/6=2/3-x
- (x+1)^(2/3)-(x-1)^(2/3)=0
- (x+2)/5-(3x+2)/6=2/3-x
- 2/3-(x-1/21)=2
- (x-2)/5-(3x+2)/6=2/3+x
(x-2)/5-(3x+2)/6=2/3-x equation
The teacher will be very surprised to see your correct solution 😉
The solution
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x - 2 3*x + 2 ----- - ------- = 2/3 - x 5 6
$$\frac{x - 2}{5} - \frac{3 x + 2}{6} = - x + \frac{2}{3}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- \frac{3 x}{10} = - x + \frac{7}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{7 x}{10} = \frac{7}{5}$$
Divide both parts of the equation by 7/10
We get the answer: x = 2
(x-2)/5-(3*x+2)/6 = 2/3-x
Expand brackets in the left part
x/5-2/5-3*x/6-2/6 = 2/3-x
Looking for similar summands in the left part:
-11/15 - 3*x/10 = 2/3-x
Move free summands (without x)
from left part to right part, we given:
$$- \frac{3 x}{10} = - x + \frac{7}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{7 x}{10} = \frac{7}{5}$$
Divide both parts of the equation by 7/10
x = 7/5 / (7/10)
We get the answer: x = 2
The graph