(x-6)^2-x*(x+8)=2 equation
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The solution
Detail solution
Given the equation:
(x-6)^2-x*(x+8) = 2
Expand expressions:
36 + x^2 - 12*x - x*(x + 8) = 2
36 + x^2 - 12*x - x^2 - 8*x = 2
Reducing, you get:
34 - 20*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 20 x = -34$$
Divide both parts of the equation by -20
x = -34 / (-20)
We get the answer: x = 17/10
$$x_{1} = \frac{17}{10}$$
Sum and product of roots
[src]
$$0 + \frac{17}{10}$$
$$\frac{17}{10}$$
$$1 \cdot \frac{17}{10}$$
$$\frac{17}{10}$$