Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation x-y=7
-
Equation 1/(x-1)^2+2/(x-1)-3=0
-
Equation 1/(x+6)=2
-
Equation (x-4)^2-x^2=0
- Express {x} in terms of y where:
- 7*x-1*y=-7
- 10*x-15*y=16
- -14*x-12*y=5
- 19*x-12*y=16
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Identical expressions
- (x- six) three = twenty-five (x+ six)
- (x minus 6)3 equally 25(x plus 6)
- (x minus six) three equally twenty minus five (x plus six)
- x-63=25x+6
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Similar expressions
- x^2-2*x-63=0
- x^2+2*x-63=0
- (x-6)^3=16(x+6)
- ((x+2)^2+2):((x^2)-1+((25x+6):x^4))=0
- (x-6)3=25(x-6)
- 12cosx-6*(3)^(1/2)=0
- 3*75x-52/7=4,25x+61/7
- 25x+6y=13
- (x+6)3=25(x+6)
(x-6)3=25(x+6) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$3 x = 25 x + 168$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-22\right) x = 168$$
Divide both parts of the equation by -22
We get the answer: x = -84/11
(x-6)*3 = 25*(x+6)
Expand brackets in the left part
x*3-6*3 = 25*(x+6)
Expand brackets in the right part
x*3-6*3 = 25*x+25*6
Move free summands (without x)
from left part to right part, we given:
$$3 x = 25 x + 168$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-22\right) x = 168$$
Divide both parts of the equation by -22
x = 168 / (-22)
We get the answer: x = -84/11
Sum and product of roots
[src]
sum
-84 ---- 11
$$- \frac{84}{11}$$
=
-84 ---- 11
$$- \frac{84}{11}$$
product
-84 ---- 11
$$- \frac{84}{11}$$
=
-84 ---- 11
$$- \frac{84}{11}$$
-84/11