Mister Exam

Other calculators


(x-1)^3-x^2*(x-4)-(x+2)*(x-2)=0

(x-1)^3-x^2*(x-4)-(x+2)*(x-2)=0 equation

The teacher will be very surprised to see your correct solution 😉

v

Numerical solution:

Do search numerical solution at [, ]

The solution

You have entered [src]
       3    2                              
(x - 1)  - x *(x - 4) - (x + 2)*(x - 2) = 0
$$- x^{2} \left(x - 4\right) - \left(x + 2\right) \left(x - 2\right) + \left(x - 1\right)^{3} = 0$$
Detail solution
Given the equation:
(x-1)^3-x^2*(x-4)-(x+2)*(x-2) = 0

Expand expressions:
- 1 + x^3 - 3*x^2 + 3*x - x^2*(x - 1*4) - (x + 2)*(x - 1*2) = 0

- 1 + x^3 - 3*x^2 + 3*x - x^3 + 4*x^2 - (x + 2)*(x - 1*2) = 0

- 1 + x^3 - 3*x^2 + 3*x - x^3 + 4*x^2 + 4 - x^2 = 0

Reducing, you get:
3 + 3*x = 0

Move free summands (without x)
from left part to right part, we given:
$$3 x = -3$$
Divide both parts of the equation by 3
x = -3 / (3)

We get the answer: x = -1
The graph
Rapid solution [src]
x1 = -1
$$x_{1} = -1$$
Sum and product of roots [src]
sum
0 - 1
$$-1 + 0$$
=
-1
$$-1$$
product
1*-1
$$1 \left(-1\right)$$
=
-1
$$-1$$
-1
Numerical answer [src]
x1 = -1.0
x1 = -1.0
The graph
(x-1)^3-x^2*(x-4)-(x+2)*(x-2)=0 equation