Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 4-6*(x+2)=3-5*x
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Equation 1/(x-3)^2-3/(x-3)-4=0
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Equation 2-3(7+2x)=11
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Equation x^2-2x+1=0
- Express {x} in terms of y where:
- 17*x-20*y=6
- 5*x-13*y=17
- 6*x+17*y=3
- 1*x+4*y=20
- Derivative of:
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5/2
- Integral of d{x}:
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5/2
- Sum of series:
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5/2
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Identical expressions
- (x- one)/(4x- one)= five / two
- (x minus 1) divide by (4x minus 1) equally 5 divide by 2
- (x minus one) divide by (4x minus one) equally five divide by two
- x-1/4x-1=5/2
- (x-1) divide by (4x-1)=5 divide by 2
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Similar expressions
- (x-1)/(4x+1)=5/2
- sqrt((3x-5)/(2x))=1/3
- (x-5)/2=2*(3*x/7-1/2)/3
- sinx+((2-(3)^0,5)/2*(cosx+1))^0,5=0
- 1*((x-2)*(x-3)*(x-4)*(x-5))/24+13*((x-1)*(x-3)*(x-4)*(x-5))/(-6)+29*((x-1)*(x-2)*(x-4)*(x-5))/4+49*((x-1)*(x-2)*(x-3)*(x-5))/(-6)+73*((x-1)*(x-2)*(x-3)*(x-4))/24=0
- (x+1)/(4x-1)=5/2
(x-1)/(4x-1)=5/2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x - 1}{4 x - 1} = \frac{5}{2}$$
Multiply the equation sides by the denominator -1 + 4*x
we get:
$$x - 1 = 10 x - \frac{5}{2}$$
Move free summands (without x)
from left part to right part, we given:
$$x = 10 x - \frac{3}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-9\right) x = - \frac{3}{2}$$
Divide both parts of the equation by -9
We get the answer: x = 1/6
$$\frac{x - 1}{4 x - 1} = \frac{5}{2}$$
Multiply the equation sides by the denominator -1 + 4*x
we get:
$$x - 1 = 10 x - \frac{5}{2}$$
Move free summands (without x)
from left part to right part, we given:
$$x = 10 x - \frac{3}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-9\right) x = - \frac{3}{2}$$
Divide both parts of the equation by -9
x = -3/2 / (-9)
We get the answer: x = 1/6
Sum and product of roots
[src]
sum
1/6
$$\frac{1}{6}$$
=
1/6
$$\frac{1}{6}$$
product
1/6
$$\frac{1}{6}$$
=
1/6
$$\frac{1}{6}$$
1/6