Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x²-4x+3=0
-
Equation 12-y+2=0
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Equation -2*x^2/(x^2-1)^2+1/(x^2-1)=0
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Equation x^3+9*x^2+27*x+27=0
- Express {x} in terms of y where:
- -7*x-5*y=-17
- -4*x+19*y=-3
- -1*x-11*y=19
- -1*x-5*y=-4
- Sum of series:
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100
- Integral of d{x}:
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100
- Canonical form:
- 100
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Identical expressions
- (x- four) two +(y+ three) two = one hundred
- (x minus 4)2 plus (y plus 3)2 equally 100
- (x minus four) two plus (y plus three) two equally one hundred
- x-42+y+32=100
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Similar expressions
- (x-4)2-(y+3)2=100
- (x-4)2+(y-3)2=100
- (x+4)2+(y+3)2=100
(x-4)2+(y+3)2=100 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
(x - 4)*2 + (y + 3)*2 = 100
$$2 \left(x - 4\right) + 2 \left(y + 3\right) = 100$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$2 x + 2 y = 102$$
Move the summands with the other variables
from left part to right part, we given:
$$2 x = \left(-2\right) y + 102$$
Divide both parts of the equation by 2
We get the answer: x = 51 - y
(x-4)*2+(y+3)*2 = 100
Expand brackets in the left part
x*2-4*2+y*2+3*2 = 100
Looking for similar summands in the left part:
-2 + 2*x + 2*y = 100
Move free summands (without x)
from left part to right part, we given:
$$2 x + 2 y = 102$$
Move the summands with the other variables
from left part to right part, we given:
$$2 x = \left(-2\right) y + 102$$
Divide both parts of the equation by 2
x = 102 - 2*y / (2)
We get the answer: x = 51 - y
The graph
Sum and product of roots
[src]
sum
51 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 51$$
=
51 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 51$$
product
51 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 51$$
=
51 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 51$$
51 - re(y) - i*im(y)
Rapid solution
[src]
x1 = 51 - re(y) - I*im(y)
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 51$$
x1 = -re(y) - i*im(y) + 51