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x-4+5(x+3)=5(-1-x)-2 equation

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Numerical solution:

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The solution

You have entered [src]
x - 4 + 5*(x + 3) = 5*(-1 - x) - 2
$$\left(x - 4\right) + 5 \left(x + 3\right) = 5 \left(- x - 1\right) - 2$$
Detail solution
Given the linear equation:
x-4+5*(x+3) = 5*(-1-x)-2

Expand brackets in the left part
x-4+5*x+5*3 = 5*(-1-x)-2

Expand brackets in the right part
x-4+5*x+5*3 = -5*1-5*x-2

Looking for similar summands in the left part:
11 + 6*x = -5*1-5*x-2

Looking for similar summands in the right part:
11 + 6*x = -7 - 5*x

Move free summands (without x)
from left part to right part, we given:
$$6 x = - 5 x - 18$$
Move the summands with the unknown x
from the right part to the left part:
$$11 x = -18$$
Divide both parts of the equation by 11
x = -18 / (11)

We get the answer: x = -18/11
The graph
Sum and product of roots [src]
sum
-18 
----
 11 
$$- \frac{18}{11}$$
=
-18 
----
 11 
$$- \frac{18}{11}$$
product
-18 
----
 11 
$$- \frac{18}{11}$$
=
-18 
----
 11 
$$- \frac{18}{11}$$
-18/11
Rapid solution [src]
     -18 
x1 = ----
      11 
$$x_{1} = - \frac{18}{11}$$
x1 = -18/11
Numerical answer [src]
x1 = -1.63636363636364
x1 = -1.63636363636364