(x-5)*(x-3)-(x+1)*(x-4)=6 equation
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The solution
Detail solution
Given the equation:
(x-5)*(x-3)-(x+1)*(x-4) = 6
Expand expressions:
15 + x^2 - 8*x - (x + 1)*(x - 4) = 6
15 + x^2 - 8*x + 4 - x^2 + 3*x = 6
Reducing, you get:
13 - 5*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = -13$$
Divide both parts of the equation by -5
x = -13 / (-5)
We get the answer: x = 13/5
Sum and product of roots
[src]
$$\frac{13}{5}$$
$$\frac{13}{5}$$
$$\frac{13}{5}$$
$$\frac{13}{5}$$