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(x-5)*(x-3)-(x+1)*(x-4)=6 equation

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Numerical solution:

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The solution

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(x - 5)*(x - 3) - (x + 1)*(x - 4) = 6
$$\left(x - 5\right) \left(x - 3\right) - \left(x - 4\right) \left(x + 1\right) = 6$$
Detail solution
Given the equation:
(x-5)*(x-3)-(x+1)*(x-4) = 6

Expand expressions:
15 + x^2 - 8*x - (x + 1)*(x - 4) = 6

15 + x^2 - 8*x + 4 - x^2 + 3*x = 6

Reducing, you get:
13 - 5*x = 0

Move free summands (without x)
from left part to right part, we given:
$$- 5 x = -13$$
Divide both parts of the equation by -5
x = -13 / (-5)

We get the answer: x = 13/5
The graph
Sum and product of roots [src]
sum
13/5
$$\frac{13}{5}$$
=
13/5
$$\frac{13}{5}$$
product
13/5
$$\frac{13}{5}$$
=
13/5
$$\frac{13}{5}$$
13/5
Rapid solution [src]
x1 = 13/5
$$x_{1} = \frac{13}{5}$$
x1 = 13/5
Numerical answer [src]
x1 = 2.6
x1 = 2.6