Mister Exam
Other calculators
-
How to use it?
- Equation:
- Equation x+y=5
-
Equation x^2+5x+6=0
-
Equation 1*(x-1)*(x-3)=0
-
Equation 5x+12=8x+30
- Express {x} in terms of y where:
- -14*x-8*y=20
- -2*x-19*y=3
- 8*x+6*y=20
- -11*x-19*y=14
- Integral of d{x}:
- (x-8)^2
- Sum of series:
- (x-8)^2
-
Identical expressions
- (x- eight)^ two
- (x minus 8) squared
- (x minus eight) to the power of two
- (x-8)2
- x-82
- (x-8)²
- (x-8) to the power of 2
- x-8^2
-
Similar expressions
- (x+8)^2
(x-8)^2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(x - 8\right)^{2} = 0$$
We get the quadratic equation
$$x^{2} - 16 x + 64 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -16$$
$$c = 64$$
, then
Because D = 0, then the equation has one root.
$$x_{1} = 8$$
$$\left(x - 8\right)^{2} = 0$$
We get the quadratic equation
$$x^{2} - 16 x + 64 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -16$$
$$c = 64$$
, then
D = b^2 - 4 * a * c =
(-16)^2 - 4 * (1) * (64) = 0
Because D = 0, then the equation has one root.
x = -b/2a = --16/2/(1)
$$x_{1} = 8$$