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(x−14,9)⋅(9,8+2x)=0 equation

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Numerical solution:

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The solution

You have entered [src]
/    149\                 
|x - ---|*(49/5 + 2*x) = 0
\     10/                 
$$\left(x - \frac{149}{10}\right) \left(2 x + \frac{49}{5}\right) = 0$$
Detail solution
Expand the expression in the equation
$$\left(x - \frac{149}{10}\right) \left(2 x + \frac{49}{5}\right) = 0$$
We get the quadratic equation
$$2 x^{2} - 20 x - \frac{7301}{50} = 0$$
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = -20$$
$$c = - \frac{7301}{50}$$
, then
D = b^2 - 4 * a * c = 

(-20)^2 - 4 * (2) * (-7301/50) = 39204/25

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = \frac{149}{10}$$
$$x_{2} = - \frac{49}{10}$$
Sum and product of roots [src]
sum
  49   149
- -- + ---
  10    10
$$- \frac{49}{10} + \frac{149}{10}$$
=
10
$$10$$
product
-49*149
-------
 10*10 
$$- \frac{7301}{100}$$
=
-7301 
------
 100  
$$- \frac{7301}{100}$$
-7301/100
Rapid solution [src]
     -49 
x1 = ----
      10 
$$x_{1} = - \frac{49}{10}$$
     149
x2 = ---
      10
$$x_{2} = \frac{149}{10}$$
x2 = 149/10
Numerical answer [src]
x1 = -4.9
x2 = 14.9
x2 = 14.9