2(x+2)-4(6-x)=0 equation
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The solution
Detail solution
Given the linear equation:
2*(x+2)-4*(6-x) = 0
Expand brackets in the left part
2*x+2*2-4*6+4*x = 0
Looking for similar summands in the left part:
-20 + 6*x = 0
Move free summands (without x)
from left part to right part, we given:
$$6 x = 20$$
Divide both parts of the equation by 6
x = 20 / (6)
We get the answer: x = 10/3
Sum and product of roots
[src]
$$\frac{10}{3}$$
$$\frac{10}{3}$$
$$\frac{10}{3}$$
$$\frac{10}{3}$$