(2x+7)^2=(2x-1)^2 equation
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The solution
Detail solution
Given the equation:
(2*x+7)^2 = (2*x-1)^2
Expand expressions:
49 + 4*x^2 + 28*x = (2*x-1)^2
(2*x+7)^2 = 1 - 4*x + 4*x^2
Reducing, you get:
48 + 32*x = 0
Move free summands (without x)
from left part to right part, we given:
$$32 x = -48$$
Divide both parts of the equation by 32
x = -48 / (32)
We get the answer: x = -3/2
$$x_{1} = - \frac{3}{2}$$
Sum and product of roots
[src]
$$- \frac{3}{2}$$
$$- \frac{3}{2}$$
$$- \frac{3}{2}$$
$$- \frac{3}{2}$$