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Equation:
Equation x^4-4x^2+4=0
Equation x^4=(3x-10)^2
Equation (x+1)+(x+3)=5
Equation 6x^2+x-7=0
Express {x} in terms of y where:
5*x+11*y=6
19*x-8*y=12
20*x+10*y=-3
-4*x+8*y=-5
Identical expressions
(two x+ one)*(one +sqrt((two x+ one)^2+ seven)+x*sqrt(x^2+ seven))= one
(2x plus 1) multiply by (1 plus square root of ((2x plus 1) squared plus 7) plus x multiply by square root of (x squared plus 7)) equally 1
(two x plus one) multiply by (one plus square root of ((two x plus one) squared plus seven) plus x multiply by square root of (x squared plus seven)) equally one
(2x+1)*(1+√((2x+1)^2+7)+x*√(x^2+7))=1
(2x+1)*(1+sqrt((2x+1)2+7)+x*sqrt(x2+7))=1
2x+1*1+sqrt2x+12+7+x*sqrtx2+7=1
(2x+1)*(1+sqrt((2x+1)²+7)+x*sqrt(x²+7))=1
(2x+1)*(1+sqrt((2x+1) to the power of 2+7)+x*sqrt(x to the power of 2+7))=1
(2x+1)(1+sqrt((2x+1)^2+7)+xsqrt(x^2+7))=1
(2x+1)(1+sqrt((2x+1)2+7)+xsqrt(x2+7))=1
2x+11+sqrt2x+12+7+xsqrtx2+7=1
2x+11+sqrt2x+1^2+7+xsqrtx^2+7=1
Similar expressions
(2x+1)*(1+sqrt((2x-1)^2+7)+x*sqrt(x^2+7))=1
(2x+1)*(1+sqrt((2x+1)^2+7)-x*sqrt(x^2+7))=1
(2x+1)*(1+sqrt((2x+1)^2+7)+x*sqrt(x^2-7))=1
(2x-1)*(1+sqrt((2x+1)^2+7)+x*sqrt(x^2+7))=1
(2x+1)*(1-sqrt((2x+1)^2+7)+x*sqrt(x^2+7))=1
(2x+1)*(1+sqrt((2x+1)^2-7)+x*sqrt(x^2+7))=1

(2x+1)(1+sqrt((2x+1)^2+7)+xsqrt(x^2+7))=1 equation

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(2*x + 1)*\1 + \/  (2*x + 1)  + 7  + x*\/  x  + 7 / = 1

$$\left(2 x + 1\right) \left(x \sqrt{x^{2} + 7} + \left(\sqrt{\left(2 x + 1\right)^{2} + 7} + 1\right)\right) = 1$$

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(2x+1)*(1+sqrt((2x+1)^2+7)+x*sqrt(x^2+7))=1 equation

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The solution

(2x+1)(1+sqrt((2x+1)^2+7)+xsqrt(x^2+7))=1 equation