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(2x+5)(x-6)+2(3x+2)(3x-2)=5(2x+1)^2+11

(2x+5)(x-6)+2(3x+2)(3x-2)=5(2x+1)^2+11 equation

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Numerical solution:

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The solution

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                                                       2     
(2*x + 5)*(x - 6) + 2*(3*x + 2)*(3*x - 2) = 5*(2*x + 1)  + 11
$$\left(x - 6\right) \left(2 x + 5\right) + \left(3 x - 2\right) 2 \left(3 x + 2\right) = 5 \left(2 x + 1\right)^{2} + 11$$
Simplify
Detail solution
Given the equation:
(2*x+5)*(x-6)+2*(3*x+2)*(3*x-2) = 5*(2*x+1)^2+11

Expand expressions:
- 30 - 7*x + 2*x^2 + (2*(3*x + 2))*(3*x - 2) = 5*(2*x+1)^2+11

- 30 - 7*x + 2*x^2 + - 8 + 18*x^2 = 5*(2*x+1)^2+11

(2*x+5)*(x-6)+2*(3*x+2)*(3*x-2) = 5 + 20*x + 20*x^2 + 11

Reducing, you get:
-54 - 27*x = 0

Move free summands (without x)
from left part to right part, we given:
$$- 27 x = 54$$
Divide both parts of the equation by -27
x = 54 / (-27)

We get the answer: x = -2
The graph
Plot the graph f1(x)
Plot the graph f2(x)
Rapid solution [src] 
x1 = -2
$$x_{1} = -2$$ 
x1 = -2
Sum and product of roots [src] 
sum
-2
$$-2$$ 
=
-2
$$-2$$ 
product
-2
$$-2$$ 
=
-2
$$-2$$ 
-2
Numerical answer [src] 
x1 = -2.0
x1 = -2.0
The graph
(2x+5)(x-6)+2(3x+2)(3x-2)=5(2x+1)^2+11 equation
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