Given the equation:
$$\left(2 x - \frac{1}{x}\right) + 6 = 2$$
Multiply the equation sides by the denominators:
and x
we get:
$$x \left(\left(2 x - \frac{1}{x}\right) + 6\right) = 2 x$$
$$2 x^{2} + 6 x - 1 = 2 x$$
Move right part of the equation to
left part with negative sign.
The equation is transformed from
$$2 x^{2} + 6 x - 1 = 2 x$$
to
$$2 x^{2} + 4 x - 1 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 4$$
$$c = -1$$
, then
D = b^2 - 4 * a * c =
(4)^2 - 4 * (2) * (-1) = 24
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = -1 + \frac{\sqrt{6}}{2}$$
$$x_{2} = - \frac{\sqrt{6}}{2} - 1$$