Mister Exam
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- Equation:
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Equation 0,6-1,6(x-4)=3(7-0,4x)
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Equation 4^(x-1/2)-6*2^(x-1)+3=0
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Equation 5x+4=x+12
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Equation 5x-25+2x²=17+13x
- Express {x} in terms of y where:
- -17*x+20*y=-6
- -19*x-18*y=-2
- -19*x-12*y=-1
- -10*x+14*y=17
- Derivative of:
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5-7x
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Identical expressions
- (two x- five)^ two -(x- one)(4x+2)= five -7x
- (2x minus 5) squared minus (x minus 1)(4x plus 2) equally 5 minus 7x
- (two x minus five) to the power of two minus (x minus one)(4x plus 2) equally five minus 7x
- (2x-5)2-(x-1)(4x+2)=5-7x
- 2x-52-x-14x+2=5-7x
- (2x-5)²-(x-1)(4x+2)=5-7x
- (2x-5) to the power of 2-(x-1)(4x+2)=5-7x
- 2x-5^2-x-14x+2=5-7x
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Similar expressions
- (2x+5)^2-(x-1)(4x+2)=5-7x
- (2x-5)^2+(x-1)(4x+2)=5-7x
- (2x-5)^2-(x-1)(4x-2)=5-7x
- (2x-5)^2-(x+1)(4x+2)=5-7x
- (2x^2-5-7)(x-1)=0
- 6x+12-3x=5-(7x+6)
- (2x-5)^2-(x-1)(4x+2)=5+7x
(2x-5)^2-(x-1)(4x+2)=5-7x equation
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The solution
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2 (2*x - 5) - (x - 1)*(4*x + 2) = 5 - 7*x
$$- \left(x - 1\right) \left(4 x + 2\right) + \left(2 x - 5\right)^{2} = 5 - 7 x$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$- 11 x = -22$$
Divide both parts of the equation by -11
We get the answer: x = 2
(2*x-5)^2-(x-1)*(4*x+2) = 5-7*x
Expand expressions:
25 - 20*x + 4*x^2 - (x - 1)*(4*x + 2) = 5-7*x
25 - 20*x + 4*x^2 + 2 - 4*x^2 + 2*x = 5-7*x
Reducing, you get:
22 - 11*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 11 x = -22$$
Divide both parts of the equation by -11
x = -22 / (-11)
We get the answer: x = 2