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2^2x-2n=16 equation

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Numerical solution:

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The solution

You have entered [src]
4*x - 2*n = 16
$$- 2 n + 4 x = 16$$
Detail solution
Given the linear equation:
2^2*x-2*n = 16

Move the summands with the other variables
from left part to right part, we given:
$$4 x = 2 n + 16$$
Divide both parts of the equation by 4
x = 16 + 2*n / (4)

We get the answer: x = 4 + n/2
The graph
Rapid solution [src]
         re(n)   I*im(n)
x1 = 4 + ----- + -------
           2        2   
$$x_{1} = \frac{\operatorname{re}{\left(n\right)}}{2} + \frac{i \operatorname{im}{\left(n\right)}}{2} + 4$$
x1 = re(n)/2 + i*im(n)/2 + 4
Sum and product of roots [src]
sum
    re(n)   I*im(n)
4 + ----- + -------
      2        2   
$$\frac{\operatorname{re}{\left(n\right)}}{2} + \frac{i \operatorname{im}{\left(n\right)}}{2} + 4$$
=
    re(n)   I*im(n)
4 + ----- + -------
      2        2   
$$\frac{\operatorname{re}{\left(n\right)}}{2} + \frac{i \operatorname{im}{\left(n\right)}}{2} + 4$$
product
    re(n)   I*im(n)
4 + ----- + -------
      2        2   
$$\frac{\operatorname{re}{\left(n\right)}}{2} + \frac{i \operatorname{im}{\left(n\right)}}{2} + 4$$
=
    re(n)   I*im(n)
4 + ----- + -------
      2        2   
$$\frac{\operatorname{re}{\left(n\right)}}{2} + \frac{i \operatorname{im}{\left(n\right)}}{2} + 4$$
4 + re(n)/2 + i*im(n)/2