2+√2sin(x)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{2 \sin{\left(x \right)}} + 2 = 0$$
transform
$$\sqrt{2} \sqrt{\sin{\left(x \right)}} + 2 = 0$$
$$\sqrt{2 \sin{\left(x \right)}} + 2 = 0$$
Do replacement
$$w = \sin{\left(x \right)}$$
Given the equation
$$\sqrt{2} \sqrt{w} + 2 = 0$$
Because equation degree is equal to = 1/2 and the free term = -2 < 0,
so the real solutions of the equation d'not exist
do backward replacement
$$\sin{\left(x \right)} = w$$
Given the equation
$$\sin{\left(x \right)} = w$$
- this is the simplest trigonometric equation
This equation is transformed to
$$x = 2 \pi n + \operatorname{asin}{\left(w \right)}$$
$$x = 2 \pi n - \operatorname{asin}{\left(w \right)} + \pi$$
Or
$$x = 2 \pi n + \operatorname{asin}{\left(w \right)}$$
$$x = 2 \pi n - \operatorname{asin}{\left(w \right)} + \pi$$
, where n - is a integer
substitute w:
Sum and product of roots
[src]
$$0$$
$$0$$
$$1$$
$$1$$