Mister Exam
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How to use it?
- Equation:
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Equation 13/(x-4)=2
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Equation x/4+x=4
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Equation x^2+11=0
- Equation x+y=5
- Express {x} in terms of y where:
- 6*x+17*y=-11
- -12*x-10*y=-16
- 15*x+10*y=-4
- 15*x+9*y=5
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Identical expressions
- (two +14x)/ two =(8x- ten)/ three
- (2 plus 14x) divide by 2 equally (8x minus 10) divide by 3
- (two plus 14x) divide by two equally (8x minus ten) divide by three
- 2+14x/2=8x-10/3
- (2+14x) divide by 2=(8x-10) divide by 3
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Similar expressions
- (2+14x)/2=(8x+10)/3
- (2-14x)/2=(8x-10)/3
(2+14x)/2=(8x-10)/3 equation
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The solution
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2 + 14*x 8*x - 10 -------- = -------- 2 3
$$\frac{14 x + 2}{2} = \frac{8 x - 10}{3}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$7 x = \frac{8 x}{3} - \frac{13}{3}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{13 x}{3} = - \frac{13}{3}$$
Divide both parts of the equation by 13/3
We get the answer: x = -1
(2+14*x)/2 = (8*x-10)/3
Expand brackets in the left part
2/2+14*x/2 = (8*x-10)/3
Expand brackets in the right part
2/2+14*x/2 = 8*x/3-10/3
Move free summands (without x)
from left part to right part, we given:
$$7 x = \frac{8 x}{3} - \frac{13}{3}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{13 x}{3} = - \frac{13}{3}$$
Divide both parts of the equation by 13/3
x = -13/3 / (13/3)
We get the answer: x = -1