2(n-3)=3(4-n)+5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
2*(n-3) = 3*(4-n)+5
Expand brackets in the left part
2*n-2*3 = 3*(4-n)+5
Expand brackets in the right part
2*n-2*3 = 3*4-3*n+5
Looking for similar summands in the right part:
-6 + 2*n = 17 - 3*n
Move free summands (without n)
from left part to right part, we given:
$$2 n = 23 - 3 n$$
Move the summands with the unknown n
from the right part to the left part:
$$5 n = 23$$
Divide both parts of the equation by 5
n = 23 / (5)
We get the answer: n = 23/5
Sum and product of roots
[src]
$$\frac{23}{5}$$
$$\frac{23}{5}$$
$$\frac{23}{5}$$
$$\frac{23}{5}$$