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2(n-3)=3(4-n)+5 equation

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Numerical solution:

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The solution

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2*(n - 3) = 3*(4 - n) + 5
$$2 \left(n - 3\right) = 3 \left(4 - n\right) + 5$$
Detail solution
Given the linear equation:
2*(n-3) = 3*(4-n)+5

Expand brackets in the left part
2*n-2*3 = 3*(4-n)+5

Expand brackets in the right part
2*n-2*3 = 3*4-3*n+5

Looking for similar summands in the right part:
-6 + 2*n = 17 - 3*n

Move free summands (without n)
from left part to right part, we given:
$$2 n = 23 - 3 n$$
Move the summands with the unknown n
from the right part to the left part:
$$5 n = 23$$
Divide both parts of the equation by 5
n = 23 / (5)

We get the answer: n = 23/5
The graph
Rapid solution [src]
n1 = 23/5
$$n_{1} = \frac{23}{5}$$
n1 = 23/5
Sum and product of roots [src]
sum
23/5
$$\frac{23}{5}$$
=
23/5
$$\frac{23}{5}$$
product
23/5
$$\frac{23}{5}$$
=
23/5
$$\frac{23}{5}$$
23/5
Numerical answer [src]
n1 = 4.6
n1 = 4.6