2-2(2x-5)=3(3-5x) equation
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The solution
Detail solution
Given the linear equation:
2-2*(2*x-5) = 3*(3-5*x)
Expand brackets in the left part
2-2*2*x+2*5 = 3*(3-5*x)
Expand brackets in the right part
2-2*2*x+2*5 = 3*3-3*5*x
Looking for similar summands in the left part:
12 - 4*x = 3*3-3*5*x
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = - 15 x - 3$$
Move the summands with the unknown x
from the right part to the left part:
$$11 x = -3$$
Divide both parts of the equation by 11
x = -3 / (11)
We get the answer: x = -3/11
$$x_{1} = - \frac{3}{11}$$
Sum and product of roots
[src]
$$- \frac{3}{11}$$
$$- \frac{3}{11}$$
$$- \frac{3}{11}$$
$$- \frac{3}{11}$$