2/3(19-x)+3/5x=12/19*19 equation
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The solution
Detail solution
Given the linear equation:
2/3*(19-x)+3/5*x = 12/19*19
Expand brackets in the left part
2/3*19-2/3*x+3/5*x = 12/19*19
Looking for similar summands in the left part:
38/3 - x/15 = 12/19*19
Move free summands (without x)
from left part to right part, we given:
$$- \frac{x}{15} = - \frac{2}{3}$$
Divide both parts of the equation by -1/15
x = -2/3 / (-1/15)
We get the answer: x = 10
Sum and product of roots
[src]
$$10$$
$$10$$
$$10$$
$$10$$