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- Equation:
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Equation (x-1)*(x^2+8*x+16)=6*(x+4)
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Equation 2*(-4*x^2/(x^2-4)+1+(x^2+4)*(4*x^2/(x^2-4)-1)/(x^2-4))/(x^2-4)=0
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Equation 4(x+6)=x
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Equation x^2-5*x-1=0
- Express {x} in terms of y where:
- 11*x-2*y=9
- 17*x+14*y=6
- -18*x-1*y=-12
- -1*x+18*y=-13
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Identical expressions
- two ,8x- ten =- zero ,6x+ eighteen
- 2,8x minus 10 equally minus 0,6x plus 18
- two ,8x minus ten equally minus zero ,6x plus eighteen
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Similar expressions
- 2,8x-10=+0,6x+18
- 2,8x+10=-0,6x+18
- 2,8x-10=-0,6x-18
2,8x-10=-0,6x+18 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
14*x 3*x ---- - 10 = - --- + 18 5 5
$$\frac{14 x}{5} - 10 = 18 - \frac{3 x}{5}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{14 x}{5} = 28 - \frac{3 x}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{17 x}{5} = 28$$
Divide both parts of the equation by 17/5
We get the answer: x = 140/17
(14/5)*x-10 = -(3/5)*x+18
Expand brackets in the left part
14/5x-10 = -(3/5)*x+18
Expand brackets in the right part
14/5x-10 = -3/5x+18
Move free summands (without x)
from left part to right part, we given:
$$\frac{14 x}{5} = 28 - \frac{3 x}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{17 x}{5} = 28$$
Divide both parts of the equation by 17/5
x = 28 / (17/5)
We get the answer: x = 140/17
Sum and product of roots
[src]
sum
140 --- 17
$$\frac{140}{17}$$
=
140 --- 17
$$\frac{140}{17}$$
product
140 --- 17
$$\frac{140}{17}$$
=
140 --- 17
$$\frac{140}{17}$$
140/17