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How to use it?
- Equation:
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Equation x^6=(3x-2)^3
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Equation 2x^2+5x-2=0
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Equation 1/4*x^2-4=0
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Equation x^2-10x=0
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Identical expressions
- twenty-three - four ,6x= three ,6x- nineteen
- 23 minus 4,6x equally 3,6x minus 19
- twenty minus three minus four ,6x equally three ,6x minus nineteen
-
Similar expressions
- 23-4,6x=3,6x+19
- 23+4,6x=3,6x-19
23-4,6x=3,6x-19 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
23*x 18*x
23 - ---- = ---- - 19
5 5
$$23 - \frac{23 x}{5} = \frac{18 x}{5} - 19$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$- \frac{23 x}{5} = \frac{18 x}{5} - 42$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-41\right) x}{5} = -42$$
Divide both parts of the equation by -41/5
We get the answer: x = 210/41
23-(23/5)*x = (18/5)*x-19
Expand brackets in the left part
23-23/5x = (18/5)*x-19
Expand brackets in the right part
23-23/5x = 18/5x-19
Move free summands (without x)
from left part to right part, we given:
$$- \frac{23 x}{5} = \frac{18 x}{5} - 42$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-41\right) x}{5} = -42$$
Divide both parts of the equation by -41/5
x = -42 / (-41/5)
We get the answer: x = 210/41
Sum and product of roots
[src]
sum
210 --- 41
$$\frac{210}{41}$$
=
210 --- 41
$$\frac{210}{41}$$
product
210 --- 41
$$\frac{210}{41}$$
=
210 --- 41
$$\frac{210}{41}$$
210/41