Mister Exam
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How to use it?
- Equation:
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Equation (x^2+3)/(x^2+1)=2
-
Equation -x=3,5
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Equation z^2+z+2=0
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Equation 7*x^2-28=0
- Express {x} in terms of y where:
- 13*x-13*y=-18
- -2*x+12*y=1
- -15*x+17*y=-9
- -3*x+20*y=5
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Identical expressions
- twelve , one -(x+ five , eight)= one , seven
- 12,1 minus (x plus 5,8) equally 1,7
- twelve , one minus (x plus five , eight) equally one , seven
- 12,1-x+5,8=1,7
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Similar expressions
- 12,1+(x+5,8)=1,7
- 12,1-(x-5,8)=1,7
12,1-(x+5,8)=1,7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
121 17 --- + -x - 29/5 = -- 10 10
$$\left(- x - \frac{29}{5}\right) + \frac{121}{10} = \frac{17}{10}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$- x = - \frac{23}{5}$$
Divide both parts of the equation by -1
We get the answer: x = 23/5
(121/10)-(x+(29/5)) = (17/10)
Expand brackets in the left part
121/10-x-29/5) = (17/10)
Expand brackets in the right part
121/10-x-29/5) = 17/10
Move free summands (without x)
from left part to right part, we given:
$$- x = - \frac{23}{5}$$
Divide both parts of the equation by -1
x = -23/5 / (-1)
We get the answer: x = 23/5
Sum and product of roots
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sum
23/5
$$\frac{23}{5}$$
=
23/5
$$\frac{23}{5}$$
product
23/5
$$\frac{23}{5}$$
=
23/5
$$\frac{23}{5}$$
23/5
The graph