Mister Exam
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How to use it?
- Equation:
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Equation 6*x^2+x-1=0
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Equation 12-x=x
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Equation 12-(4-x)^2=x*(3-x)
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Equation |x|=-2
- Express {x} in terms of y where:
- -17*x+2*y=-4
- 15*x-5*y=-5
- 12*x-20*y=10
- -7*x+15*y=18
- Limit of the function:
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x*(3-x)
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Identical expressions
- twelve -(four -x)^ two =x*(three -x)
- 12 minus (4 minus x) squared equally x multiply by (3 minus x)
- twelve minus (four minus x) to the power of two equally x multiply by (three minus x)
- 12-(4-x)2=x*(3-x)
- 12-4-x2=x*3-x
- 12-(4-x)²=x*(3-x)
- 12-(4-x) to the power of 2=x*(3-x)
- 12-(4-x)^2=x(3-x)
- 12-(4-x)2=x(3-x)
- 12-4-x2=x3-x
- 12-4-x^2=x3-x
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Similar expressions
- 12-(4+x)^2=x*(3-x)
- x^3-x^2+10*x-8=0
- -x^3-x^2+121*x+121=0
- 12+(4-x)^2=x*(3-x)
- 12-(4-x)^2=x*(3+x)
- x^3-x^2+x-1=0
- x^3-x^2-x+2
12-(4-x)^2=x*(3-x) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 12 - (4 - x) = x*(3 - x)
$$12 - \left(4 - x\right)^{2} = x \left(3 - x\right)$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$5 x = 4$$
Divide both parts of the equation by 5
We get the answer: x = 4/5
12-(4-x)^2 = x*(3-x)
Expand expressions:
12 - 16 - x^2 + 8*x = x*(3-x)
12-(4-x)^2 = -x^2 + 3*x
Reducing, you get:
-4 + 5*x = 0
Move free summands (without x)
from left part to right part, we given:
$$5 x = 4$$
Divide both parts of the equation by 5
x = 4 / (5)
We get the answer: x = 4/5
Sum and product of roots
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sum
4/5
$$\frac{4}{5}$$
=
4/5
$$\frac{4}{5}$$
product
4/5
$$\frac{4}{5}$$
=
4/5
$$\frac{4}{5}$$
4/5
The graph