Mister Exam
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How to use it?
- Equation:
-
Equation t-4/25=8
-
Equation x^2+15=0
-
Equation x^2+5*x-14=0
-
Equation k^2+k=0
- Express {x} in terms of y where:
- 18*x+20*y=-13
- 6*x-13*y=-14
- -4*x+1*y=-6
- 1*x+15*y=7
-
Identical expressions
- twelve - five (x+ one)= seven +3x-2x
- 12 minus 5(x plus 1) equally 7 plus 3x minus 2x
- twelve minus five (x plus one) equally seven plus 3x minus 2x
- 12-5x+1=7+3x-2x
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Similar expressions
- 12-5(x+1)=7-3x-2x
- 12+5(x+1)=7+3x-2x
- 12-5(x+1)=7+3x+2x
- 12-5(x-1)=7+3x-2x
12-5(x+1)=7+3x-2x equation
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The solution
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12 - 5*(x + 1) = 7 + 3*x - 2*x
$$12 - 5 \left(x + 1\right) = - 2 x + \left(3 x + 7\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-6\right) x = 0$$
Divide both parts of the equation by -6
We get the answer: x = 0
12-5*(x+1) = 7+3*x-2*x
Expand brackets in the left part
12-5*x-5*1 = 7+3*x-2*x
Looking for similar summands in the left part:
7 - 5*x = 7+3*x-2*x
Looking for similar summands in the right part:
7 - 5*x = 7 + x
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-6\right) x = 0$$
Divide both parts of the equation by -6
x = 0 / (-6)
We get the answer: x = 0
The graph