Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation -x=0
-
Equation 8*x=56
-
Equation 5*x=50
-
Equation x^2=17
- Express {x} in terms of y where:
- -12*x+4*y=16
- -19*x+6*y=-17
- 10*x+11*y=-11
- -17*x-15*y=-11
-
Identical expressions
- twelve -(3x²+5x)+(-8x+3x²)= zero
- 12 minus (3x² plus 5x) plus ( minus 8x plus 3x²) equally 0
- twelve minus (3x² plus 5x) plus ( minus 8x plus 3x²) equally zero
- 12-3x²+5x+-8x+3x²=0
- 12-(3x²+5x)+(-8x+3x²)=O
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Similar expressions
- 12-(3x²-5x)+(-8x+3x²)=0
- 12+(3x²+5x)+(-8x+3x²)=0
- 12-(3x²+5x)+(-8x-3x²)=0
- 12-(3x²+5x)-(-8x+3x²)=0
- 12-(3x²+5x)+(8x+3x²)=0
12-(3x²+5x)+(-8x+3x²)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 2 12 + - 3*x - 5*x + -8*x + 3*x = 0
$$\left(3 x^{2} - 8 x\right) + \left(\left(- 3 x^{2} - 5 x\right) + 12\right) = 0$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 13 x = -12$$
Divide both parts of the equation by -13
We get the answer: x = 12/13
12-(3*x^2+5*x)+(-8*x+3*x^2) = 0
Expand brackets in the left part
12-3*x-2-5*x+-8*x+3*x+2 = 0
Looking for similar summands in the left part:
12 - 13*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 13 x = -12$$
Divide both parts of the equation by -13
x = -12 / (-13)
We get the answer: x = 12/13
Sum and product of roots
[src]
sum
12 -- 13
$$\frac{12}{13}$$
=
12 -- 13
$$\frac{12}{13}$$
product
12 -- 13
$$\frac{12}{13}$$
=
12 -- 13
$$\frac{12}{13}$$
12/13