Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (5*x+4)/2+3=9*x/4
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Equation -2*(-2-y)-y-2=0
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Equation 2*x^2+18*x=0
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Equation x^3+x^2-x-2=0
- Express {x} in terms of y where:
- -7*x-15*y=-6
- -17*x+7*y=0
- -8*x-4*y=-3
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Identical expressions
- (three x- two)/ eight =(2x+ one)/3
- (3x minus 2) divide by 8 equally (2x plus 1) divide by 3
- (three x minus two) divide by eight equally (2x plus one) divide by 3
- 3x-2/8=2x+1/3
- (3x-2) divide by 8=(2x+1) divide by 3
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Similar expressions
- 2x+1/3-2=9
- (3x-2)/8=(2x-1)/3
- 2x+1/3+3x-6/3=5
- (x+3)/7=((3x)-2)/8
- 2*x+1/3=(3*x+2)/4
- (3x+2)/8=(2x+1)/3
(3x-2)/8=(2x+1)/3 equation
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The solution
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3*x - 2 2*x + 1 ------- = ------- 8 3
$$\frac{3 x - 2}{8} = \frac{2 x + 1}{3}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{8} = \frac{2 x}{3} + \frac{7}{12}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-7\right) x}{24} = \frac{7}{12}$$
Divide both parts of the equation by -7/24
We get the answer: x = -2
(3*x-2)/8 = (2*x+1)/3
Expand brackets in the left part
3*x/8-2/8 = (2*x+1)/3
Expand brackets in the right part
3*x/8-2/8 = 2*x/3+1/3
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{8} = \frac{2 x}{3} + \frac{7}{12}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-7\right) x}{24} = \frac{7}{12}$$
Divide both parts of the equation by -7/24
x = 7/12 / (-7/24)
We get the answer: x = -2