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3*x^3*(x^2-4*x+5)-x^2*(3*x^3-12*x^2+4)+x*(4*x-15*x^2-5)-55=0 equation

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Numerical solution:

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The solution

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3*x *\x  - 4*x + 5/ - x *\3*x  - 12*x  + 4/ + x*\4*x - 15*x  - 5/ - 55 = 0
$$\left(x \left(\left(- 15 x^{2} + 4 x\right) - 5\right) + \left(- x^{2} \left(\left(3 x^{3} - 12 x^{2}\right) + 4\right) + 3 x^{3} \left(\left(x^{2} - 4 x\right) + 5\right)\right)\right) - 55 = 0$$
Detail solution
Given the equation:
3*x^3*(x^2-4*x+5)-x^2*(3*x^3-12*x^2+4)+x*(4*x-15*x^2-5)-55 = 0

Expand expressions:
- 5*x - 55 = 0

Reducing, you get:
-55 - 5*x = 0

Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 55$$
Divide both parts of the equation by -5
x = 55 / (-5)

We get the answer: x = -11
The graph
Rapid solution [src]
x1 = -11
$$x_{1} = -11$$
x1 = -11
Sum and product of roots [src]
sum
-11
$$-11$$
=
-11
$$-11$$
product
-11
$$-11$$
=
-11
$$-11$$
-11
Numerical answer [src]
x1 = -11.0
x1 = -11.0