Mister Exam
Other calculators
-
How to use it?
- Equation:
- Equation z^3+i=0
-
Equation (5x-2)*(-x+3)=0
-
Equation 1-x/2=x/3
-
Equation 3x-2(3x-2)=19
- Express {x} in terms of y where:
- -1*x-6*y=18
- -14*x+18*y=0
- -8*x+3*y=-4
- -16*x-10*y=4
- Graphing y =:
- 5-2x
- Integral of d{x}:
- 5-2x
-
Identical expressions
- three *(x+ five)= five -2x
- 3 multiply by (x plus 5) equally 5 minus 2x
- three multiply by (x plus five) equally five minus 2x
- 3(x+5)=5-2x
- 3x+5=5-2x
-
Similar expressions
- 2-3*(x+2)=5-2*x
- 3*(x+5)=5+2x
- sin(3*x+5*pi/2)+cos(7*p+x)=sqrt(3)*cos(7*p/2+x)
- 3^(3*x+5)=9^4*x
- 3*(x-5)=5-2x
- 25^(x-1)+sqrt(1/(25^(-2*x)))=475+(1/5)^(1-2*x)
- 3x+5
- x^2+3*x+5=0
3*(x+5)=5-2x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$3 x = - 2 x - 10$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = -10$$
Divide both parts of the equation by 5
We get the answer: x = -2
3*(x+5) = 5-2*x
Expand brackets in the left part
3*x+3*5 = 5-2*x
Move free summands (without x)
from left part to right part, we given:
$$3 x = - 2 x - 10$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = -10$$
Divide both parts of the equation by 5
x = -10 / (5)
We get the answer: x = -2