3*|x|-5,1=|4,2| equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$3 x - \frac{93}{10} = 0$$
after simplifying we get
$$3 x - \frac{93}{10} = 0$$
the solution in this interval:
$$x_{1} = \frac{31}{10}$$
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$3 \left(- x\right) - \frac{93}{10} = 0$$
after simplifying we get
$$- 3 x - \frac{93}{10} = 0$$
the solution in this interval:
$$x_{2} = - \frac{31}{10}$$
The final answer:
$$x_{1} = \frac{31}{10}$$
$$x_{2} = - \frac{31}{10}$$
Sum and product of roots
[src]
$$- \frac{31}{10} + \frac{31}{10}$$
$$0$$
$$- \frac{961}{100}$$
$$- \frac{961}{100}$$
$$x_{1} = - \frac{31}{10}$$
$$x_{2} = \frac{31}{10}$$