Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 15-x=8
-
Equation x^2+3*x+9=0
-
Equation x^2-16*x+64=0
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Equation x^2-6x-7=0
- Express {x} in terms of y where:
- 9*x-8*y=-6
- -11*x+1*y=-14
- -13*x-14*y=0
- 7*x-17*y=2
-
Identical expressions
- three - four (one -6x)= two (3x+ four)
- 3 minus 4(1 minus 6x) equally 2(3x plus 4)
- three minus four (one minus 6x) equally two (3x plus four)
- 3-41-6x=23x+4
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Similar expressions
- 3+4(1-6x)=2(3x+4)
- 2*(3*x+4)/(2*sqrt(x)-x)=0
- 7*(5x+24)^(1/2)-2*(3x+4)+7x=-2*3*(5x+24)^(1/2)+4
- ((x-2)^3)*(x+4)^2=0
- (31/3+21/4x)*(-12)=-48-(23x+4,4)
- 3-4(1-6x)=2(3x-4)
- 3-4(1+6x)=2(3x+4)
3-4(1-6x)=2(3x+4) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
3 - 4*(1 - 6*x) = 2*(3*x + 4)
$$3 - 4 \left(1 - 6 x\right) = 2 \left(3 x + 4\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$24 x = 6 x + 9$$
Move the summands with the unknown x
from the right part to the left part:
$$18 x = 9$$
Divide both parts of the equation by 18
We get the answer: x = 1/2
3-4*(1-6*x) = 2*(3*x+4)
Expand brackets in the left part
3-4*1+4*6*x = 2*(3*x+4)
Expand brackets in the right part
3-4*1+4*6*x = 2*3*x+2*4
Looking for similar summands in the left part:
-1 + 24*x = 2*3*x+2*4
Move free summands (without x)
from left part to right part, we given:
$$24 x = 6 x + 9$$
Move the summands with the unknown x
from the right part to the left part:
$$18 x = 9$$
Divide both parts of the equation by 18
x = 9 / (18)
We get the answer: x = 1/2
Sum and product of roots
[src]
sum
1/2
$$\frac{1}{2}$$
=
1/2
$$\frac{1}{2}$$
product
1/2
$$\frac{1}{2}$$
=
1/2
$$\frac{1}{2}$$
1/2
The graph