Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation t-4/25=8
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Equation x^2+15=0
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Equation x^2+5*x-14=0
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Equation x^2=5
- Express {x} in terms of y where:
- 18*x+20*y=-13
- -19*x-16*y=3
- -18*x+10*y=12
- 19*x-5*y=6
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Identical expressions
- three , four + two y= seven (y-2, three)
- 3,4 plus 2y equally 7(y minus 2,3)
- three , four plus two y equally seven (y minus 2, three)
- 3,4+2y=7y-2,3
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Similar expressions
- 3,4-2y=7(y-2,3)
- 3,4+2*y=7*(y-2,3)
- 3,4+2y=7(y+2,3)
3,4+2y=7(y-2,3) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
/ 23\
17/5 + 2*y = 7*|y - --|
\ 10/
$$2 y + \frac{17}{5} = 7 \left(y - \frac{23}{10}\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without y)
from left part to right part, we given:
$$2 y = 7 y - \frac{39}{2}$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-5\right) y = - \frac{39}{2}$$
Divide both parts of the equation by -5
We get the answer: y = 39/10
(17/5)+2*y = 7*(y-(23/10))
Expand brackets in the left part
17/5+2*y = 7*(y-(23/10))
Expand brackets in the right part
17/5+2*y = 7*y+7*23/10)
Move free summands (without y)
from left part to right part, we given:
$$2 y = 7 y - \frac{39}{2}$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-5\right) y = - \frac{39}{2}$$
Divide both parts of the equation by -5
y = -39/2 / (-5)
We get the answer: y = 39/10
Sum and product of roots
[src]
sum
39 -- 10
$$\frac{39}{10}$$
=
39 -- 10
$$\frac{39}{10}$$
product
39 -- 10
$$\frac{39}{10}$$
=
39 -- 10
$$\frac{39}{10}$$
39/10
The graph