Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 4-6*(x+2)=3-5*x
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Equation 4-6(x+2)=3-5x
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Equation 1+sin(x)=0
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Equation x^2-3*x+1=0
- Express {x} in terms of y where:
- 18*x-8*y=-2
- -11*x+15*y=7
- 6*x+17*y=3
- 1*x+10*y=-18
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Identical expressions
- three (2x- four)=2x-(5x+ nine)
- 3(2x minus 4) equally 2x minus (5x plus 9)
- three (2x minus four) equally 2x minus (5x plus nine)
- 32x-4=2x-5x+9
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Similar expressions
- 3(2x-4)=2x+(5x+9)
- log_3^2(x)-4log(3,x)-3=0
- (-(19/5))*(110/103)*(2*x-(47/10))=0
- 3(2x-4)=2x-(5x-9)
- 3(2x+4)=2x-(5x+9)
- 2x-5x+9=5
- 2*x-5x+9=x-2
- 5*x-8=3*(2*x-4)-x
3(2x-4)=2x-(5x+9) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
3*(2*x - 4) = 2*x + -5*x - 9
$$3 \left(2 x - 4\right) = 2 x + \left(- 5 x - 9\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$6 x = 3 - 3 x$$
Move the summands with the unknown x
from the right part to the left part:
$$9 x = 3$$
Divide both parts of the equation by 9
We get the answer: x = 1/3
3*(2*x-4) = 2*x-(5*x+9)
Expand brackets in the left part
3*2*x-3*4 = 2*x-(5*x+9)
Expand brackets in the right part
3*2*x-3*4 = 2*x-5*x-9
Looking for similar summands in the right part:
-12 + 6*x = -9 - 3*x
Move free summands (without x)
from left part to right part, we given:
$$6 x = 3 - 3 x$$
Move the summands with the unknown x
from the right part to the left part:
$$9 x = 3$$
Divide both parts of the equation by 9
x = 3 / (9)
We get the answer: x = 1/3
Sum and product of roots
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sum
1/3
$$\frac{1}{3}$$
=
1/3
$$\frac{1}{3}$$
product
1/3
$$\frac{1}{3}$$
=
1/3
$$\frac{1}{3}$$
1/3
The graph