Mister Exam
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How to use it?
- Equation:
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Equation x/3/7=9/14
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Equation 2x+9=13-x
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Equation x^2+4x+13=0
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Equation log(3-x)=-1
- Express {x} in terms of y where:
- -17*x-12*y=-4
- 2*x+13*y=-7
- 3*x-9*y=-4
- -4*x-1*y=-6
- Graphing y =:
- x-3
- Derivative of:
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x-3
- Integral of d{x}:
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x-3
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Identical expressions
- thirteen -(2x- five)=x- three
- 13 minus (2x minus 5) equally x minus 3
- thirteen minus (2x minus five) equally x minus three
- 13-2x-5=x-3
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Similar expressions
- log(x)-3+1/x=0
- 13-(2x-5)=x+3
- 13-(2x+5)=x-3
- 13+(2x-5)=x-3
13-(2x-5)=x-3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = x - 21$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-3\right) x = -21$$
Divide both parts of the equation by -3
We get the answer: x = 7
13-(2*x-5) = x-3
Expand brackets in the left part
13-2*x+5 = x-3
Looking for similar summands in the left part:
18 - 2*x = x-3
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = x - 21$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-3\right) x = -21$$
Divide both parts of the equation by -3
x = -21 / (-3)
We get the answer: x = 7
The graph