Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (2*x-6)^2-4*x^2=0
-
Equation 3*x^2+2=-5*x
-
Equation x^3+9*x^2+27*x+27=0
-
Equation x^2-7*x+6=0
- Express {x} in terms of y where:
- -20*x+6*y=-12
- -11*x+16*y=-5
- -12*x-9*y=-3
- -6*x-2*y=7
-
Identical expressions
- sqrtx- two / three = zero
- square root of x minus 2 divide by 3 equally 0
- square root of x minus two divide by three equally zero
- √x-2/3=0
- sqrtx-2/3=O
- sqrtx-2 divide by 3=0
-
Similar expressions
- sqrtx+2/3=0
sqrtx-2/3=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{x} - \frac{2}{3} = 0$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{x}\right)^{2} = \left(\frac{2}{3}\right)^{2}$$
or
$$x = \frac{4}{9}$$
We get the answer: x = 4/9
The final answer:
$$x_{1} = \frac{4}{9}$$
$$\sqrt{x} - \frac{2}{3} = 0$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{x}\right)^{2} = \left(\frac{2}{3}\right)^{2}$$
or
$$x = \frac{4}{9}$$
We get the answer: x = 4/9
The final answer:
$$x_{1} = \frac{4}{9}$$
Sum and product of roots
[src]
sum
4/9
$$\frac{4}{9}$$
=
4/9
$$\frac{4}{9}$$
product
4/9
$$\frac{4}{9}$$
=
4/9
$$\frac{4}{9}$$
4/9
Numerical answer
[src]
x1 = 0.444444444444444
x2 = 0.444444444444539 + 4.09726113892774e-13*i
x3 = 0.444444444444444 - 2.31433384328189e-17*i
x3 = 0.444444444444444 - 2.31433384328189e-17*i