Given the equation
$$\frac{\sqrt{2 x + 7}}{3} = 5$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\frac{\left(\sqrt{2 x + 7}\right)^{2}}{9} = 5^{2}$$
or
$$\frac{2 x}{9} + \frac{7}{9} = 25$$
Move free summands (without x)
from left part to right part, we given:
$$\frac{2 x}{9} = \frac{218}{9}$$
Divide both parts of the equation by 2/9
x = 218/9 / (2/9)
We get the answer: x = 109
The final answer:
$$x_{1} = 109$$